Question 474: Atoms & Nuclei

Question

When an electron is excited from its 4 th orbit to 5 th stationary orbit, the change in the angular momentum of electron is approximately.
(Planck's constant $$=h=6.63 	imes 10^{-34} \mathrm{~J}-\mathrm{s}$$ )

Accepted Answer

Charge in angular momentum is
$$\begin{array}{rlrl} 
& \Delta L=L_2-L_1=n_2 h-n_1 h \
\Rightarrow & \Delta L=h\left(n_2-n_1ight) \
\Rightarrow & \Delta L=\frac{h}{2 \pi}\left(n_2-n_1ight) \
\Rightarrow & \Delta L=\frac{6.6 	imes 10^{-34}}{2 	imes 3.14}(5-4) \
\Rightarrow & \Delta L=1 	imes 10^{-34} \mathrm{~J}-\mathrm{s}
\end{array}$$

Answer

$$2 	imes 10^{-34} \mathrm{~J}-\mathrm{s}$$

Answer

$$6.63 	imes 10^{-34} \mathrm{~J}-\mathrm{s}$$

Answer

$$1 	imes 10^{-34} \mathrm{~J}-\mathrm{s}$$

Answer

$$3.14 	imes 10^{-34} \mathrm{~J}-\mathrm{s}$$

Atoms & Nuclei

When an electron is excited from its 4 th orbit to 5 th stationary orbit, the change in the angular momentum of electron is approximately. (Planck's constant $=h=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$ )

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