Question 310: Atoms & Nuclei

Question

Assume that a neutron breaks into a proton and an electron.  The energy released during this process is : (mass of neutron $$ = 1.6725 	imes {10^{ - 27}}kg,$$ mass of proton $$ = 1.6725 	imes {10^{ - 27}}\,kg,$$ mass of electron $$ = 9 	imes {10^{ - 31}}\,kg$$ ).

Accepted Answer

$${}_0^1n 	o {}_1^1H + {}_{ - 1}{e^0} + \overrightarrow v  + Q$$
The mass defect during the process
$$\Delta m = {m_n} - {m_H} - {m_e}$$
$$ = 1.6725 	imes {10^{ - 27}} - \left( {1.6725 	imes {{10}^{ - 27}} + 9 	imes {{10}^{ - 31}}kg} ight)$$
$$ =  - 9 	imes {10^{ - 31}}kg$$
The energy released during the process
$$E = \Delta m{c^2}$$
$$E = 9 	imes {10^{ - 31}} 	imes 9 	imes {10^{16}}$$
$$ = 81 	imes {10^{ - 15}}\,joules$$
$$E = {{81 	imes {{10}^{ - 15}}} \over {1.6 	imes {{10}^{ - 19}}}} = 0.511MeV$$

Answer

$$0.51$$ $$MeV$$

Answer

$$7.10\,MeV$$

Answer

$$6.30\,MeV$$

Answer

$$5.4\,MeV$$

Atoms & Nuclei

Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (mass of neutron $ = 1.6725 \times {10^{ - 27}}kg, mass of proton = 1.6725 \times {10^{ - 27}}\,kg, mass of electron = 9 \times {10^{ - 31}}\,kg$ ).

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