Question 137: Semiconductors and Logic Gates

Question

The truth table for the circuit given in the fig. is:

Accepted Answer

C = A + B
and y = $$\overline {A.C} $$
A
B
C=(A+B)
A.C.
y=$$\overline {A.C} $$
0
0
0
0
1
0
1
1
0
1
1
0
1
1
0
1
1
1
1
0

Answer

$$\left| {\matrix{
   A & B & Y  \cr 
   0 & 0 & 1  \cr 
   0 & 1 & 1  \cr 
   1 & 0 & 1  \cr 
   1 & 1 & 1  \cr

} } \right|$$

Answer

$$\left| {\matrix{
   A & B & Y  \cr 
   0 & 0 & 1  \cr 
   0 & 1 & 0  \cr 
   1 & 0 & 0  \cr 
   1 & 1 & 0  \cr

} } \right|$$

Answer

$$\left| {\matrix{
   A & B & Y  \cr 
   0 & 0 & 1  \cr 
   0 & 1 & 1  \cr 
   1 & 0 & 0  \cr 
   1 & 1 & 0  \cr

} } \right|$$

Answer

$$\left| {\matrix{
   A & B & Y  \cr 
   0 & 0 & 0  \cr 
   0 & 1 & 0  \cr 
   1 & 0 & 1  \cr 
   1 & 1 & 1  \cr

} } \right|$$

Semiconductors and Logic Gates