Question 42: Semiconductors and Logic Gates

Question

The value of net resistance of the network as shown in the given figure is :

Accepted Answer

Here $$D_1$$ is forward wise while $$D_2$$ is reversed wise
So net resistance between end, $$R=\frac{15 	imes 10}{25}=6 \Omega$$

Answer

$$(30 / 11) \Omega$$

Answer

$$6 \Omega$$

Answer

$$(5 / 2) \Omega$$

Answer

$$(15 / 4) \Omega$$

Semiconductors and Logic Gates