Question 116: Semiconductors and Logic Gates

Question

The logic circuit shown above is equivalent to :

Accepted Answer

The logic circuit is given as
By using De-morganÃ¢ÂÂs theorem,
$$C = \overline {A + \overline B }  = \overline A .\overline{\overline B}  = \overline A .B$$
This relation can be shown by the circuit drawn below

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Semiconductors and Logic Gates

The logic circuit shown above is equivalent to :

Choose the correct answer: