Question 125: Semiconductors and Logic Gates

Question

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then
its band gap energy is :
Planck’s constant h = 6.63 $$ 	imes $$ 10–34 J.s. Speed of light c = 3 $$ 	imes $$ 108
 m/s

Accepted Answer

$$E = {{hc} \over \lambda }$$
= $${{6.63 	imes {{10}^{ - 34}} 	imes 3 	imes {{10}^8}} \over {400 	imes {{10}^{ - 9}}}}$$
= $${{1240} \over {400}}$$ eV
= 3.1 eV

Answer

1.5 eV

Answer

2.0 eV

Answer

3.1 eV

Answer

1.1 eV

Semiconductors and Logic Gates

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is : Planck’s constant h = 6.63 $ \times 10–34 J.s. Speed of light c = 3 \times $ 108 m/s

Choose the correct answer: