Question 369: AC fundamentals

Question

In the circuit given below, the current through inductor is $0.9 \mathrm{~A}$ and through the capacitor is $0.6 \mathrm{~A}$. The current drawn from the a.c. source is

Accepted Answer

As the currents in an inductor and capacitor are out of phase by $180^{\circ}$, we can write
Current through the capacitor $\mathrm{I}_{\mathrm{C}}=0.9 \mathrm{~A}$
Current through the inductor $\mathrm{I}_{\mathrm{L}}=-(0.6 \mathrm{~A})$
$\begin{aligned}
	herefore \quad 	ext { Total current drawn from the source } & =\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{L}} \
& =0.9-0.6 \
& =0.3 \mathrm{~A}
\end{aligned}$

Answer

1.5 A

Answer

0.9 A

Answer

0.6 A

Answer

0.3 A

AC fundamentals

In the circuit given below, the current through inductor is 0.9 \mathrm{~A} and through the capacitor is 0.6 \mathrm{~A}. The current drawn from the a.c. source is

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