Question 182: AC fundamentals

Question

In a transformer, number of turns in the primary coil are $140$ and that in the secondary coil are $280.$ If current in primary coil is $4A,$ then that in the secondary coil is

Accepted Answer

${N_p} = 140,\,\,{N_s} = 280,\,\,{I_p} = 4A,\,\,{I_s} = ?$
For a transformer ${{{I_s}} \over {{I_p}}} = {{{N_p}} \over {{N_s}}}$
$ \Rightarrow {{{I_s}} \over 4} = {{140} \over {280}} \Rightarrow {I_s} = 2A$

Answer

$4A$

Answer

$2A$

Answer

$6A$

Answer

$10A$

AC fundamentals

In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4A, then that in the secondary coil is

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