Question 182: AC fundamentals

Question

In a transformer, number of turns in the primary coil are $$140$$ and that in the secondary coil are $$280.$$ If current in primary coil is $$4A,$$ then that in the secondary coil is

Accepted Answer

$${N_p} = 140,\,\,{N_s} = 280,\,\,{I_p} = 4A,\,\,{I_s} = ?$$
For a transformer $${{{I_s}} \over {{I_p}}} = {{{N_p}} \over {{N_s}}}$$
$$ \Rightarrow {{{I_s}} \over 4} = {{140} \over {280}} \Rightarrow {I_s} = 2A$$

Answer

$$4A$$

Answer

$$2A$$

Answer

$$6A$$

Answer

$$10A$$

AC fundamentals

In a transformer, number of turns in the primary coil are $140 and that in the secondary coil are 280. If current in primary coil is 4A,$ then that in the secondary coil is

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