Question 2: AC fundamentals

Question

If maximum energy is stored in a capacitor
at t = 0, then find the time after which
current in the circuit will be maximum.
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Accepted Answer

Given the values :
$ L = 25 \, 	ext{mH} = 25 	imes 10^{-3} \, 	ext{H} $
$ C = 10 \, \mu	ext{F} = 10^{-5} \, 	ext{F} $
The time period $ T $ for an LC oscillation can be calculated using the formula :
$ T = 2\pi \sqrt{LC} $
Substituting the given values :
$ T = 2\pi \sqrt{25 	imes 10^{-3} 	imes 10^{-5}} = \pi 	imes 10^{-3} \, 	ext{s} = \pi \, 	ext{ms} $
For the current in the circuit to be at its maximum, it occurs at :
$ t = \frac{T}{4} = \frac{\pi}{4} \, 	ext{ms} $
Therefore, the time after which the current in the circuit will be maximum is $\frac{\pi}{4} \, 	ext{ms}$.

Answer

$\frac{\pi}{2} \mathrm{~ms}$

Answer

$\frac{\pi}{4} \mathrm{~ms}$

Answer

$\pi \mathrm{~ms}$

Answer

$2 \mathrm{~ms}$

AC fundamentals

If maximum energy is stored in a capacitor at t = 0, then find the time after which current in the circuit will be maximum.

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