Question 209: AC fundamentals

Question

In an ac generator, a rectangular coil of 100 turns each having area $14 	imes 10^{-2} \mathrm{~m}^{2}$ is rotated at $360 ~\mathrm{rev} / \mathrm{min}$ about an axis perpendicular to a uniform magnetic field of magnitude $3.0 \mathrm{~T}$. The maximum value of the emf produced will be ________ $V$.
$\left(ight.$ Take $\left.\pi=\frac{22}{7}ight)$

Accepted Answer

$$\phi=B.A$$
$$\phi=\mathrm{BNA}\cos\omega t$$
So, $$Emf = {{ - d\phi } \over {dt}} = NBA\omega \sin \omega t$$
So maximum value of emf is
$${E_{\max }} = NBA\omega $$
$$ = 100 	imes 3 	imes 14 	imes {10^{ - 2}} 	imes {{360 	imes 2\pi } \over {60}} = 1584$$

AC fundamentals

Integer / Numeric Answer Type