Question 168: AC fundamentals

Question

In the circuit shown below, the key $$K$$ is closed at $$t=0.$$ The current through the battery is

Accepted Answer

At $$t=0,$$ no current will flow through $$L$$ and $${R_1}$$
$$	herefore$$ Current through battery $$ = {V \over {{R_2}}}$$
At $$t = \infty ,$$
effective resistance, $${{\mathop{m R}
olimits} _{eff}} = {{{R_1}{R_2}} \over {{R_1} + {R_2}}}$$
$$	herefore$$ Current through battery $$ = {V \over {{{\mathop{m R}
olimits} _{eff}}}} = {{V\left( {{R_1} + {R_2}} ight)} \over {{R_1}{R_2}}}$$

Answer

$${{V{R_1}{R_2}} \over {\sqrt {R_1^2 + R_2^2} }}$$ at $$t=0$$ and $${V \over {{R_2}}}$$ at $$t = \infty $$

Answer

$${V \over {{R_2}}}$$ at $$\,t = 0$$ and $${{V\left( {{R_1} + {R_2}} \right)} \over {{R_1}{R_2}}}$$ at $$t = \infty $$

Answer

$${V \over {{R_2}}}$$ at $$\,t = 0$$  and $${{V{R_1}{R_2}} \over {\sqrt {R_1^2 + R_2^2} }}$$ at $$t = \infty $$

Answer

$${{V\left( {{R_1} + {R_2}} \right)} \over {{R_1}{R_2}}}$$ at $$t=0$$ and $${V \over {{R_2}}}$$ at $$t = \infty $$

AC fundamentals

In the circuit shown below, the key $K is closed at t=0.$ The current through the battery is

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