Question 224: AC fundamentals

Question

A 110 V, 50 Hz, AC source is connected in the circuit (as shown in figure). The current through the resistance 55 $\Omega$, at resonance in the circuit, will be __________ A.
![](https://app-content.cdn.examgoal.net/fly/@width/image/1l5bpobuh/0b5ad276-7c08-4a69-9847-c9c417ffa910/bacb9e90-fe53-11ec-b169-b5046c590266/file-1l5bpobui.png?format=png)

Accepted Answer

$
\frac{1}{Z}=\sqrt{\left(\frac{1}{X_L}-\frac{1}{X_C}ight)^2}
$
At resonance, $\mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{C}} \& \mathrm{Z} ightarrow \infty$
$	herefore \mathrm{Z}_{	ext {total circuit }} ightarrow \infty$
i.e, $\mathrm{I}=0$

AC fundamentals

A 110 V, 50 Hz, AC source is connected in the circuit (as shown in figure). The current through the resistance 55 \Omega, at resonance in the circuit, will be __________ A.

Integer / Numeric Answer Type