Question 445: AC fundamentals

Question

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure. Potential difference across L, C and R is 40V, 10V and 40V, respectively. The amplitude of current flowing through LCR series circuit is 10$$\sqrt 2 $$ A. The impedance of the circuit is :

Accepted Answer

I
0
= 10$$\sqrt 2 $$ A
I
RMS
= $${I \over {\sqrt 2 }}$$ = 10A
$${V_{RMS}} = \sqrt {V_R^2 + {{({V_L} - {V_C})}^2}} $$
$$ = \sqrt {{{(40)}^2} + {{(40 - 10)}^2}} $$
= 50 V
Impedance, $$Z = {{{V_{RMS}}} \over {{I_{RM}}}} = {{50V} \over {10V}} = 5\Omega $$

Answer

5$$\Omega$$

Answer

4$$\sqrt 2 $$ $$\Omega$$

Answer

5/$$\sqrt 2 $$ $$\Omega$$

Answer

4$$\Omega$$

AC fundamentals

Choose the correct answer: