Question 38: AC fundamentals

Question

In the series L-C-R circuit shown, the impedance is
![](https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lqbz3wri/6a1dc59d-3b99-4a5d-a6db-3fb3c665729d/2935cbe0-9e39-11ee-88dd-593bb30ed511/file-6y3zli1lqbz3wrj.png?format=png)

Accepted Answer

$\begin{aligned}
	ext { Here, } L & =1 \mathrm{H}, C=20 \mu \mathrm{F}, R=300 \Omega \
X_L & =2 \pi f L=2 \pi\left(\frac{50}{\pi}ight) 	imes 1=100 \Omega \
X_C & =\frac{1}{2 \pi f C}=\frac{1}{2 \pi\left(\frac{50}{\pi}ight) 20 	imes 10^{-6}}=500 \Omega \
\end{aligned}$
$\begin{aligned}
	ext { Impedance, } Z & =\sqrt{R^2+\left(X_C-X_Light)^2} \
& =\sqrt{(300)^2+(400)^2}=500 \Omega
\end{aligned}$

Answer

200$\Omega$

Answer

100$\Omega$

Answer

300$\Omega$

Answer

500$\Omega$

AC fundamentals

In the series L-C-R circuit shown, the impedance is

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