Question 337: Atoms & Nuclei

Question

If the binding energy of ground state electron in a hydrogen atom is $13.6\, \mathrm{eV}$, then, the energy required to remove the electron from the second excited state of $\mathrm{Li}^{2+}$ will be : $x 	imes 10^{-1} \mathrm{eV}$. The value of $x$ is ________.

Accepted Answer

$\mathrm{E}_{H}=13.6$
$$
\begin{aligned}
& \mathrm{E}_{\mathrm{Li}^{2+}}=13.6 \frac{Z^{2}}{n^{2}}=13.6 	imes \frac{9}{9}=13.6 \mathrm{eV} \\
& =136 	imes 10^{-1} \mathrm{eV}
\end{aligned}
$$

Atoms & Nuclei

If the binding energy of ground state electron in a hydrogen atom is 13.6\, \mathrm{eV}, then, the energy required to remove the electron from the second excited state of \mathrm{Li}^{2+} will be : x \times 10^{-1} \mathrm{eV}. The value of x is ________.

Integer / Numeric Answer Type