Question 165: Atoms & Nuclei

Question

Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of

Accepted Answer

$	herefore$ $R = {R_0}{A^{{1 \over 3}}}$
$ \Rightarrow {{{R_1}} \over {{R_2}}} = {\left( {{{{A_1}} \over {{A_2}}}} ight)^{{1 \over 3}}} = {\left( {{4 \over 3}} ight)^{{1 \over 3}}}$
$	herefore$ Density ratio, ${{{ho _1}} \over {{ho _2}}} = {{{A_1}/{V_1}} \over {{A_2}/{V_2}}}$
$ = \left( {{{{A_1}} \over {{A_2}}}} ight) 	imes {\left( {{{{R_2}} \over {{R_1}}}} ight)^3}$
$ = 1:1$

Answer

4 : 3

Answer

$\left(\frac{3}{4}\right)^{\frac{1}{3}}$

Answer

1 : 1

Answer

$\left(\frac{4}{3}\right)^{\frac{1}{3}}$

Atoms & Nuclei

Mass numbers of two nuclei are in the ratio of 4: 3. Their nuclear densities will be in the ratio of

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