Question 289: Atoms & Nuclei

Question

If radius of the $$\matrix{
   {27}  \cr 
   {13}  \cr

} $$ $$Al$$ nucleus is estimated to be $$3.6$$ fermi then the radius of $$\matrix{
   {125}  \cr 
   {52}  \cr

} \,Te$$ nucleus is estimated to be nearly

Accepted Answer

KEY CONCEPT :
$$R = {R_0}{\left( A ight)^{1/3}}$$
Here A = Mass number
$$	herefore$$ $${{{R_1}} \over {{R_2}}} = {\left( {{{{A_1}} \over {{A_2}}}} ight)^{1/3}}$$
$$ = {\left( {{{27} \over {125}}} ight)^{1/3}} = {3 \over 5}$$
$${R_2} = {5 \over 3} 	imes 3.6 = 6$$ fermi

Answer

$$8$$  fermi

Answer

$$6$$  fermi

Answer

$$5$$  fermi

Answer

$$4$$  fermi

Atoms & Nuclei

If radius of the $\matrix{ {27} \cr {13} \cr } Al nucleus is estimated to be 3.6 fermi then the radius of \matrix{ {125} \cr {52} \cr } \,Te$ nucleus is estimated to be nearly

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