Question 540: Atoms & Nuclei

Question

Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state.  The ratio of the wavelengths $$\lambda $$
1
: $$\lambda $$
2
emitted in the two cases is

Accepted Answer

In first case,
n
1
= 3 and n
2
= 4
$${1 \over {{\lambda _1}}} = R\left( {{1 \over {{3^2}}} - {1 \over {{4^2}}}} ight)$$ = $${{7R} \over 144}$$
In second case,
n
1
= 2 and n
2
= 3
$${1 \over {{\lambda _2}}} = R\left( {{1 \over {{2^2}}} - {1 \over {{3^2}}}} ight)$$ = $${{5R} \over {36}}$$
$$ 	herefore $$ $${{{\lambda _1}} \over {{\lambda _2}}}$$ = $${5 \over {36}} 	imes {{144} \over 7}$$ = $${20 \over 7}$$

Answer

$${7 \over 5}$$

Answer

$${27 \over 20}$$

Answer

$${27 \over 5}$$

Answer

$${20 \over 7}$$

Atoms & Nuclei

Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths $\lambda 1 : \lambda $ 2 emitted in the two cases is

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