Question 253: Atoms & Nuclei

Question

Imagine that a reactor converts all given mass into energy and that it operates at a power level of 10
9
watt. The mass of the fuel consumed per hour in the reactor will be : (velocity of light, c is 
3×10
8
m/s)

Accepted Answer

The power can be calculated by the relation
$$P = {E \over {\Delta t}} = {{\Delta m{c^2}} \over {\Delta t}}$$ ...... (1)
Therefore, from Eq. (1), the mass of the fuel consumed per hour in the reactor is
$${{\Delta m} \over {\Delta t}} = {P \over {{c^2}}} = {{{{10}^9}} \over {{{(3 	imes {{10}^8})}^2}}} = 4 	imes {10^{ - 12}}$$ g

Answer

0.96 gm

Answer

0.8 gm

Answer

4 $$ 	imes $$ 10
$$-$$2
gm

Answer

6.6 $$ 	imes $$ 10
$$-$$5
gm

Atoms & Nuclei

Imagine that a reactor converts all given mass into energy and that it operates at a power level of 10 9 watt. The mass of the fuel consumed per hour in the reactor will be : (velocity of light, c is 3×10 8 m/s)

Choose the correct answer: