Question 558: Atoms & Nuclei

Question

The energy of a hydrogen atom in the ground state is $-$ 13.6 eV.  The energy of a He
+
ion in the first excited state will be

Accepted Answer

Energy of a H-like atom in it's n
th
state is
given by,
E
n
= $ - {{13.6} \over {{n^2}}}{Z^2}$
For, first excited state of He
+
, n = 2, Z = 2
$ 	herefore $ E
He
+
= $ - {{13.6} \over {{2^2}}} 	imes {2^2}$ = -13.6 eV

Answer

$-$ 13.6 eV

Answer

$-$ 27.2 eV

Answer

$-$ 54.4 eV

Answer

$-$ 6.8 eV

Atoms & Nuclei

The energy of a hydrogen atom in the ground state is - 13.6 eV. The energy of a He + ion in the first excited state will be

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