Question 571: Atoms & Nuclei

Question

If the nucleus ${}_{13}^{27}Al$ has a nuclear radius of about 3.6 fm, them ${}_{32}^{125}Te$ would have its radius approximately as

Accepted Answer

A nucleus of mass
number A has radius
R = R
0
A
1/3
,
where R
0
= 1.2 ÃÂ 10
Ã¢ÂÂ15
m
and A = mass number
For ${}_{13}^{27}Al$, R
1
= R
0
(27)
1/3
= 3R
0
For ${}_{32}^{125}Te$, R
2
= R
0
(125)
1/3
= 5R
0
$ 	herefore $ ${{{R_2}} \over {{R_1}}} = {{5{R_0}} \over {3{R_0}}}$
$ \Rightarrow $ ${R_2} = {5 \over 3} 	imes {R_1}$ = ${5 \over 3} 	imes 3.6$ = 6.0 fm

Answer

9.6 fm

Answer

12.0 fm

Answer

4.8 fm

Answer

6.0 fm

Atoms & Nuclei

If the nucleus {}_{13}^{27}Al has a nuclear radius of about 3.6 fm, them {}_{32}^{125}Te would have its radius approximately as

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