Question 227: Atoms & Nuclei

Question

Consider an electron in a hydrogen atom revolving in its second excited state (having radius 4.65 $$\mathop A\limits^o $$). The
de-Broglie wavelength of this electron is :

Accepted Answer

For second excited state n = 3
$$mvr = {{3h} \over {2\pi }}$$ ........(1)
$$mv = {h \over \lambda }$$ .........(2)
Dividing (1) by (2), we get
$$r = {{3\lambda } \over {2\pi }}$$
$$ \Rightarrow $$ $$\lambda  = {{2\pi r} \over 3}$$ = $${{2 	imes 3.14 	imes 4.65} \over 3}$$ = 9.7 $$\mathop A\limits^o $$

Answer

6.6 $$\mathop A\limits^o $$

Answer

3.5 $$\mathop A\limits^o $$

Answer

9.7 $$\mathop A\limits^o $$

Answer

12.9 $$\mathop A\limits^o $$

Atoms & Nuclei

Consider an electron in a hydrogen atom revolving in its second excited state (having radius 4.65 $\mathop A\limits^o $). The de-Broglie wavelength of this electron is :

Choose the correct answer: