Question 312: Atoms & Nuclei

Question

The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is $$915\mathop A\limits^o$$. The longest wavelength of spectral lines in the Balmer series will be _______ $$\mathop A\limits^o$$.

Accepted Answer

$$\frac{1}{915}=R_H\left(\frac{1}{1^2}-\frac{1}{\infty^2}\right)\quad$$ (For Lyman)
$$\Rightarrow \frac{1}{\lambda}=R_H\left(\frac{1}{2^2}-\frac{1}{3^2}\right)\quad$$ (For Balmer)
$$\Rightarrow \lambda=6588$$ $$\mathop A\limits^o $$

Atoms & Nuclei

The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is $915\mathop A\limits^o. The longest wavelength of spectral lines in the Balmer series will be _______ \mathop A\limits^o$.

Integer / Numeric Answer Type