Question 170: Atoms & Nuclei

Question

A hydrogen atom in ground state absorbs 12.09 eV of energy. The orbital angular momentum of the electron is increased by :

Accepted Answer

Change in energy
$$
\begin{aligned}
&\Delta \mathrm{E}=\mathrm{E}_{\mathrm{f}}-\mathrm{E}_{2} \Rightarrow 12.09=\mathrm{E}_{\mathrm{f}}-(-13.6) \Rightarrow \mathrm{E}_{\mathrm{f}}=-1.51 \mathrm{eV} \\
&\Rightarrow \frac{-13.6}{n^{2}}=-1.51 \Rightarrow \mathrm{n}^{2}=9 \Rightarrow \mathrm{n}=3 \\
&	ext { So, } \Delta \mathrm{L}=\mathrm{L}_{\mathrm{f}}-\mathrm{L}_{\mathrm{i}} \\
&=\frac{h}{2 \pi}(3-1)=\frac{2 h}{2 \pi}=\frac{h}{\pi}=\frac{6.63 	imes 10^{-34}}{3.14}=2.11 	imes 10^{-34} \mathrm{Js}
\end{aligned}
$$

Answer

1.05 $$	imes$$ 10
$$-$$34
Js

Answer

2.11 $$	imes$$ 10
$$-$$34
Js

Answer

3.16 $$	imes$$ 10
$$-$$34
Js

Answer

4.22 $$	imes$$ 10
$$-$$34
Js

Atoms & Nuclei

A hydrogen atom in ground state absorbs 12.09 eV of energy. The orbital angular momentum of the electron is increased by :

Choose the correct answer: