Question 619: Atoms & Nuclei

Question

A nuclide at rest emits an $\alpha$-particle. In this process

Accepted Answer

As $f_{	ext {ext }}=0$, Hence $P_s=$ constant
or $\mathrm{P}_\alpha+\mathrm{P}_N=$ constant
Because nuclide was at rest before emission of $\alpha$-particle, hence according to law of conservation of momentum,
$P_\alpha+P_N=$ constant - 1
Thus, $\alpha$-particle and the nucleus move in opposite directions. Further, as $m_N \gg m_\alpha$, hence, $v_\alpha \gg v_N$

Answer

$\alpha$-particle moves with large velocity and the nucleus remains at rest.

Answer

Both $\alpha$-particle and nucleus move with equal speed in opposite directions.

Answer

Both move in opposite directions except $\alpha$-particle with greater speed.

Answer

Both move in opposite direction with greater velocity of $\alpha$-particle.

Atoms & Nuclei

A nuclide at rest emits an \alpha-particle. In this process

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