Question 599: Atoms & Nuclei

Question

A sample of radioactive element containing 4 $$ 	imes $$ 10
16
active nuclei. Half life of element is 10 days, then number of decayed nuclei after 30 days

Accepted Answer

N = 4 $$ 	imes $$ 10
16
$${\left( {{1 \over 2}} ight)^{{{30} \over {10}}}}$$ = $${1 \over 2}$$ $$ 	imes $$ 10
16
$$ 	herefore $$ Atoms decayed = 4 $$ 	imes $$ 10
16
- $${1 \over 2}$$ $$ 	imes $$ 10
16
= 3.5 $$ 	imes $$ 10
16

Answer

0.5 $$ 	imes $$ 10
16

Answer

2 $$ 	imes $$ 10
16

Answer

3.5 $$ 	imes $$ 10
16

Answer

1 $$ 	imes $$ 10
16

Atoms & Nuclei

A sample of radioactive element containing 4 $ \times $ 10 16 active nuclei. Half life of element is 10 days, then number of decayed nuclei after 30 days

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