Question 519: Atoms & Nuclei

Question

Radioactive material 'A' has decay constant '8 $\lambda $' and material 'B' has decay constant '$\lambda $'. Initially they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be e ?

Accepted Answer

Ratio of number of nuclei
${{{N_1}} \over {{N_2}}} = {{{e^{ - 8\lambda t}}} \over {{e^{ - \lambda t}}}}$ = ${{e^{ - 7\lambda t}}}$
According to question,
${{e^{ - 7\lambda t}}}$ = ${1 \over e}$
$ \Rightarrow $ t = ${1 \over {7\lambda }}$

Answer

${1 \over {7\lambda }}$

Answer

${1 \over {8\lambda }}$

Answer

${1 \over {9\lambda }}$

Answer

${1 \over {\lambda }}$

Atoms & Nuclei

Radioactive material 'A' has decay constant '8 \lambda ' and material 'B' has decay constant '\lambda '. Initially they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be e ?

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