Question 473: Atoms & Nuclei

Question

The energy levels with transitions for the atom are shown. The transitions corresponding to emission of radiation of maximum and minimum wavelength are respectively

Accepted Answer

As, we know that the difference of energy between two level is equal to the energy of photon.
$$\begin{aligned}
& \Delta E=h v=\frac{h c}{\lambda} \Rightarrow \lambda=\frac{h c}{\Delta E} \
	ext{or}\quad& \lambda \propto \frac{1}{\Delta E}
\end{aligned}$$
The value of $\Delta E$ is minimum for $A$, so radiation corresponding to $A$ have maximum wavelength and value of $\Delta E$ is maximum for $D$, so radiation corresponding to $D$ have minimum wavelength.

Answer

B, C

Answer

A, C

Answer

C, D

Answer

A, D

Atoms & Nuclei

The energy levels with transitions for the atom are shown. The transitions corresponding to emission of radiation of maximum and minimum wavelength are respectively

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