Question 348: Atoms & Nuclei

Question

In the hydrogen spectrum, $\lambda$ be the wavelength of first transition line of Lyman series. The wavelength difference will be "a$\lambda$'' between the wavelength of $3^{	ext {rd }}$ transition line of Paschen series and that of $2^{	ext {nd }}$ transition line of Balmer series where $\mathrm{a}=$ ___________.

Accepted Answer

${1 \over \lambda } = {R_H}\left( {{1 \over {{1^2}}} - {1 \over {{2^2}}}} ight)$
${1 \over {{\lambda _3}}} = {R_H}\left( {{1 \over {{3^2}}} - {1 \over {{6^2}}}} ight)$
${1 \over {{\lambda _2}}} = {R_H}\left( {{1 \over {{2^2}}} - {1 \over {{4^2}}}} ight)$
$	herefore$ ${\lambda _3} - {\lambda _2} = a\lambda $
$a = 5$

Atoms & Nuclei

Integer / Numeric Answer Type