Question 528: Atoms & Nuclei

Question

If radius of the $${}_{13}^{27}$$ Al nucleus is taken to be R
Al
, then
the radius of $${}_{53}^{125}$$Te nucleus is nearly

Accepted Answer

As we know, R = R
0
(A)
1/3
where A = mass number
R
Al
= R
0
(27)
1/3
= 3R
0
R
Te
= R
0
(125)
1/3
= 5R
0
= $${5 \over 3}{R_{Al}}$$

Answer

$${3 \over 5}{R_{Al}}$$

Answer

$${\left( {{{13} \over {53}}} \right)^{1/3}}{R_{Al}}$$

Answer

$${\left( {{{53} \over {13}}} \right)^{1/3}}{R_{Al}}$$

Answer

$${5 \over 3}{R_{Al}}$$

Atoms & Nuclei