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Class 12 • Physics • Chapter-12
Atoms & Nuclei
Question 240 of 680
240
Medium
JEE Mains
2019
Consider the nuclear fission Ne 20 $
\to
$ 2He 4 + C 12 Given that the binding energy/ nucleon of Ne 20 , He 4 and C 12 are, respectively, 8.03 MeV, 7.07 MeV and 7.86 MeV, identify the correct statement -
Choose the correct answer:
A
8.3 MeV energy will be released
B
energy of 11.9 MeV has to be supplied
C
energy of 12.4 MeV will be supplied
D
energy of 3.6 MeV will be released
Select an answer first
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