Question 684: Centre of Mass and Rotational Motion

Question

The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing  from the edge of the disc and normal to the disc is

Accepted Answer

Moment of Inertia of uniform circular disc
with radius Ã¢ÂÂRÃ¢ÂÂ and mass Ã¢ÂÂMÃ¢ÂÂ about axis passing
through C.M. and normal to disc will be :
I
CM
= (1/2) MR
2
Moment of Inertia about axis tangential to disc :
I
T
= I
CM
+ MR
2
I
T
= (1/2) MR
2
+ MR
2
= (3/2) MR
2

Answer

MR
2

Answer

$${1 \over 2}$$ MR
2

Answer

$${3 \over 2}$$ MR
2

Answer

$${7 \over 2}$$ MR
2

Centre of Mass and Rotational Motion

The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

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