Question 242: Centre of Mass and Rotational Motion

Question

A machine gun fires a bullet of mass $40$ $g$ with a velocity  $1200m{s^{ - 1}}.$ The man holding it can exert a maximum force of $144$ $N$ on the gun. How many bullets can he fire per second at the most?

Accepted Answer

Assume the man can fire $n$ bullets in one second.
$	herefore$ change in momentum per second $ = n 	imes mv = F$
[ $m=$ mass of bullet, $v=$ velocity, $F$ = force)  ]
$	herefore$ $n = {F \over {mv}} = {{144 	imes 1000} \over {40 	imes 1200}} = 3$

Answer

Two

Answer

Four

Answer

One

Answer

Three

Centre of Mass and Rotational Motion

A machine gun fires a bullet of mass 40 g with a velocity 1200m{s^{ - 1}}. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

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