Question 279: Centre of Mass and Rotational Motion

Question

Two particles A, B are moving on two concentric circles of radii R
1
and R
2
with equal angular speed $\omega $. At t = 0, their positions and direction of motion are shown in the figure. :
The relative velocity ${\overrightarrow V _A} - {\overrightarrow V _B}$ at t = ${\pi  \over {2\omega }}$ is given by :
![](https://imagex.cdn.examgoal.net/3N4WptKuideQHcSAr/ZVQj2asciHTizQo1CNN1182xhyWhd/gOlInscCzeBti7sbY0pxte/image.png)

Accepted Answer

$	heta $ = $\omega $t = $\omega $ ${\pi  \over {2\omega }}$ = ${\pi  \over 2}$
$\overrightarrow V $
A
$-$ $\overrightarrow V $
S
= $\omega $R
1
($-$$\widehat i$) $-$ $\omega $R
2
($-$i)
![](https://imagex.cdn.examgoal.net/87p0aSPXe1miqSSny/A70YWU25thC2DtBgGqfYVsOXe0zcW/yOLFeixVc3QT1ECHJuQqjJ/image.png)

Answer

$ - \omega \left( {{R_1} + {R_2}} \right)\,\widehat i$

Answer

$\omega \left( {{R_2} - {R_1}} \right)\,\widehat i$

Answer

$\omega \left( {{R_1} + {R_2}} \right)\,\widehat i$

Answer

$\omega \left( {{R_1} - {R_1}} \right)\,\widehat i$

Centre of Mass and Rotational Motion

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