Question 280: Centre of Mass and Rotational Motion

Question

Two particles A, B are moving on two concentric circles of radii R
1
and R
2
with equal angular speed $$\omega $$. At t = 0, their positions and direction of motion are shown in the figure. :
The relative velocity $${\overrightarrow V _A} - {\overrightarrow V _B}$$ at t = $${\pi  \over {2\omega }}$$ is given by :

Accepted Answer

$$	heta $$ = $$\omega $$t = $$\omega $$ $${\pi  \over {2\omega }}$$ = $${\pi  \over 2}$$
$$\overrightarrow V $$
A
$$-$$ $$\overrightarrow V $$
S
= $$\omega $$R
1
($$-$$$$\widehat i$$) $$-$$ $$\omega $$R
2
($$-$$i)

Answer

$$ - \omega \left( {{R_1} + {R_2}} \right)\,\widehat i$$

Answer

$$\omega \left( {{R_2} - {R_1}} \right)\,\widehat i$$

Answer

$$\omega \left( {{R_1} + {R_2}} \right)\,\widehat i$$

Answer

$$\omega \left( {{R_1} - {R_1}} \right)\,\widehat i$$

Centre of Mass and Rotational Motion

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