Question 301: Centre of Mass and Rotational Motion

Question

A body A, of mass m = 0.1 kg has an initial
velocity of 3$$\widehat i$$ ms
-1
. It collides elastically with
another body, B of the same mass which has
an initial velocity of 5$$\widehat j$$ ms
-1
. After collision,
A moves with a velocity $$\overrightarrow v  = 4\left( {\widehat i + \widehat j} \right)$$. The
energy of B after collision is written as $${x \over {10}}$$. The value of x is ___________.

Accepted Answer

By conservation of linear momentum :
(0.1)(3$$\widehat i$$) + (0.1)(5$$\widehat j$$) = (0.1)(4)($$\widehat i$$ + $$\widehat j$$) + (0.1)$$\overrightarrow v $$
$$ \Rightarrow $$ $$\overrightarrow v  =  - \widehat i + \widehat j$$
$$ 	herefore $$ $$\left| {\overrightarrow v } ight|$$ = $$\sqrt 2 $$
KE
B
= $${1 \over 2} 	imes 0.1 	imes {\left( {\sqrt 2 } ight)^2}$$ = $${1 \over {10}}$$ J
$$ 	herefore $$ x = 1

Centre of Mass and Rotational Motion

Integer / Numeric Answer Type