Question 709: Current Electricity

Question

Two batteries of different emfs and different internal resistance are connected as shown. The voltage across AB in volts is __________.

Accepted Answer

Applying Kirchhoff's second law for closed loop CDEFC we get
$$ - 3 - 2I - I + 6 = 0$$
$$I = {{6 - 3} \over 3} = 1A$$
For the lower path
$${V_A} - 3 - 2 	imes 1 = {V_B}$$
$$	herefore$$ $${V_A} - {V_B} = 5V$$
We can also find the V
AB
by considering the upper path
For the upper path,
$${V_A} - 6 + 1 	imes 1 = {V_B}$$
$${V_A} - {V_B} = 5V$$

Current Electricity

Two batteries of different emfs and different internal resistance are connected as shown. The voltage across AB in volts is __________.

Integer / Numeric Answer Type