Question 490: Current Electricity

Question

A galvanometer has resistance $80 \Omega$ and it is shunted with resistance $20 \Omega$. If $20 \%$ of the main current flows through galvanometer, then what is the value of main current?

Accepted Answer

$$
\begin{array}{ll} 
& \mathrm{I}=\mathrm{I}_1+\mathrm{I}_2 \
& \mathrm{I}_1=0.2 \mathrm{I} \quad 	herefore \quad \mathrm{I}_2=0.8 \mathrm{I} \
& 	ext { Also, } \mathrm{I}_1 \mathrm{G}=\mathrm{I}_2 \mathrm{~S} \
	herefore \quad & 0.2 \mathrm{I} 	imes 80=0.8 \mathrm{I} 	imes 20 \
	herefore \quad & \mathrm{I}=1 \mathrm{~A}
\end{array}
$$

Answer

0.2 A

Answer

0.8 A

Answer

1 A

Answer

1.2 A

Current Electricity

A galvanometer has resistance 80 \Omega and it is shunted with resistance 20 \Omega. If 20 \% of the main current flows through galvanometer, then what is the value of main current?

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