Question 307: Current Electricity

Question

The given potentiometer has its wire of resistance 10$\Omega$. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2$\Omega$ resistor is :

Accepted Answer

${{20 - {V_0}} \over 5} + {{0 - {V_0}} \over 5} + {{20 - {V_0}} \over 2} = 0$
$4 + 10 = {{2{V_0}} \over 5} + {{{V_0}} \over 2}$
$14 = {{4{V_0} + 5{V_0}} \over {10}}$
${V_0} = {{140} \over 9}$ Volt
Potential difference across 2$\Omega$ resistor is 20 $-$ V
0
That is $\left( {20 - {{140} \over 9}} \right)$ Volt
Hence answer is $\left( {{{40} \over 9}} \right)$ Volt

Answer

10 V

Answer

5 V

Answer

${{40} \over 9}$ V

Answer

${{40} \over 11}$ V

Current Electricity

The given potentiometer has its wire of resistance 10\Omega. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2\Omega resistor is :

Choose the correct answer: