Question 563: Current Electricity

Question

A galvanometer of resistance $50 \Omega$ is converted to an ammeter. After shunting, the effective resistance of ammeter is $2.5 \Omega$. The value of shunt is

Accepted Answer

The resistance of the galvanometer and the shunt are in parallel. Their equivalent resistance is given by
$\begin{array}{rlrl} 
& \frac{1}{R}=\frac{1}{G}+\frac{1}{S} \
	herefore  \frac{1}{S} & =\frac{1}{R}-\frac{1}{G} \
	herefore  \frac{1}{S} & =\frac{1}{2.5}-\frac{1}{50}=\frac{19}{50} \quad 	herefore S=\frac{50}{19} \Omega\end{array}$

Answer

$\frac{100}{19} \Omega$

Answer

$\frac{50}{19} \Omega$

Answer

$\frac{25}{19} \Omega$

Answer

$\frac{75}{19} \Omega$

Current Electricity

A galvanometer of resistance 50 \Omega is converted to an ammeter. After shunting, the effective resistance of ammeter is 2.5 \Omega. The value of shunt is

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