Question 452: Current Electricity

Question

If in the circuit, power dissipation is $150W,$ then $R$ is
![](https://imagex.cdn.examgoal.net/YWnB11KxQalZuuzpx/DyLoDjtTSMy4vVvzYB6JIWaZpocFt/2iIAqCskor5KzKKxWYGnht/image.png)

Accepted Answer

The equivalent resistance is ${{\mathop{m R}
olimits} _{eq}} = {{2 	imes R} \over {2 + R}}$
$	herefore$ Powder dissipation $P = {{{V^2}} \over {{{\mathop{m R}
olimits} _{eq}}}}$
$	herefore$  $150 = {{15 	imes 15} \over {{R_{eq}}}}$
$	herefore$ ${{\mathop{m R}
olimits} _{eq}} = {{15} \over {10}} = {3 \over 2}$
$ \Rightarrow {{2R} \over {2 + R}} = {3 \over 2}$
$ \Rightarrow 4R = 6 + 3R$
$ \Rightarrow R = 6\Omega $

Answer

$2\,\Omega $

Answer

$6\,\Omega $

Answer

$5\,\Omega $

Answer

$4\,\Omega $

Current Electricity

If in the circuit, power dissipation is 150W, then R is

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