Question 661: Current Electricity

Question

A current of 3 amp. flows through the 2 $\Omega $ resistor shown in the circuit. The power dissipated in the 5 $\Omega $ resistor is

Accepted Answer

Clearly, 2$\Omega $ , 4$\Omega $ and  ( 1 + 5) $\Omega $ resistors are in parallel. Hence, potential difference is same across each of them.
$ 	herefore $  I
1
ÃÂ 2 = I
2
ÃÂ 4 = I
3
ÃÂ 6
Given I
1
= 3A    $ 	herefore $ I
1
ÃÂ 2 = I
3
ÃÂ 6
Given I
1
= 3A.
$ 	herefore $ I
1
ÃÂ 2 = I
3
ÃÂ 6 provides
${I_3} = {{{I_1} 	imes 2} \over 6} = {{3 	imes 2} \over 6} = 1A$
Now, the potential across the 5$\Omega$ resistor is
V = I
3
ÃÂ 5 = 1 ÃÂ 5 = 5V.
$ 	herefore $ the power dissipated in the 5$\Omega$ resistor
$P = {{{V^2}} \over R} = {{{5^2}} \over 5} = 5\,watt.$

Answer

1 watt

Answer

5 watt

Answer

4 watt

Answer

2 watt

Current Electricity

A current of 3 amp. flows through the 2 \Omega resistor shown in the circuit. The power dissipated in the 5 \Omega resistor is

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