Question 674: Current Electricity

Question

For the network shown in the figure the value of the current $$i$$ is

Accepted Answer

It is a balanced Wheatstone bridge. Hence resistance 4$$\Omega $$ can be eliminated.
$$ 	herefore $$ $${R_{eq}} = {{6 	imes 9} \over {6 + 9}} = {{18} \over 5}$$
$$ 	herefore i = {V \over {{R_{eq}}}} = {{5V} \over {18}}$$

Answer

$${{9V} \over {35}}$$

Answer

$${{18V} \over 5}$$

Answer

$${{5V} \over 9}$$

Answer

$${{5V} \over {18}}$$

Current Electricity

For the network shown in the figure the value of the current $i$ is

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