Question 446: Current Electricity

Question

An ammeter reads upto $1$ ampere. Its internal resistance is $0.81$ $ohm$. To increase the range to $10$ $A$ the value of the required shunt is

Accepted Answer

${i_g} 	imes G = \left( {i - {i_g}} ight)S$
$	herefore$ $S = {{{i_g} 	imes G} \over {i - {i_g}}} = {{1 	imes 0.81} \over {10 - 1}} = 0.09\Omega $

Answer

$0.03\,\Omega $

Answer

$0.3\,\Omega $

Answer

$0.9\,\Omega $

Answer

$0.09\,\Omega $

Current Electricity