Question 516: Current Electricity

Question

In the following circuit, the current $\mathrm{I_2}$ is

Accepted Answer

$$\begin{aligned}
&	ext { Applying Kirchhoff's voltage law in loop } 1 	ext { and } 2\
&\begin{array}{ll}
	herefore & 28 \mathrm{I}_1=-6-8=-\frac{1}{2} \mathrm{~A} \
	herefore & 54 \mathrm{I}_2=-6-12=-\frac{1}{3} \mathrm{~A} \
	herefore & \mathrm{I}_3=\mathrm{I}_1+\mathrm{I}_2=-\frac{1}{2}+\left(-\frac{1}{3}ight)=-\frac{5}{6} \mathrm{~A}
\end{array}
\end{aligned}$$

Answer

5 A

Answer

3 A

Answer

$-$3A

Answer

$-\frac{5}{6}$ A

Current Electricity

In the following circuit, the current \mathrm{I_2} is

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