Question 551: Current Electricity

Question

In potentiometer experiment, cells of e.m.f. '$E_1$' and '$E_2$' are connected in series $\left(E_1>E_2\right)$ the balancing length is $64 \mathrm{~cm}$ of the wire. If the polarity of $E_2$ is reversed, the balancing length becomes $32 \mathrm{~cm}$. The ratio $\frac{E_1}{E_2}$ is

Accepted Answer

$\frac{\mathrm{E}_1}{\mathrm{E}_2}=\frac{\ell_1+\ell_2}{\ell_1+\ell_2}=\frac{64+32}{64-32}=\frac{96}{32}=3$

Answer

$1: 1$

Answer

$6: 1$

Answer

$3: 1$

Answer

$2: 1$

Current Electricity

In potentiometer experiment, cells of e.m.f. 'E_1' and 'E_2' are connected in series \left(E_1>E_2\right) the balancing length is 64 \mathrm{~cm} of the wire. If the polarity of E_2 is reversed, the balancing length becomes 32 \mathrm{~cm}. The ratio \frac{E_1}{E_2} is

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