Question 540: Current Electricity

Question

Five current carrying conductors meet at a point '$$\mathrm{O}$$' as shown in figure. The magnitude and direction of the current in conductor '$$O P$$' is

Accepted Answer

Using Kirchhoff's current Law,
Current flowing in = Current flowing out $$10+2.5+5=6+x$$
$$	herefore \quad x=17.5-6$$
$$\begin{aligned}
	herefore \quad \mathrm{x} & =17.5-6 \
& =11.5 \mathrm{~A}
\end{aligned}$$
$$	herefore \quad$$ Magnitude and direction of the current in 'OP' should be $$11.5 \mathrm{~A}$$ from $$\mathrm{O}$$ to $$\mathrm{P}$$.

Answer

$$6.5 \mathrm{~A}$$ from $$\mathrm{O}$$ to $$\mathrm{P}$$.

Answer

$$9 \mathrm{~A}$$ from $$\mathrm{P}$$ to $$\mathrm{O}$$.

Answer

$$10.5 \mathrm{~A}$$ from $$\mathrm{P}$$ to $$\mathrm{O}$$.

Answer

$$11.5 \mathrm{~A}$$ from $$\mathrm{O}$$ to $$\mathrm{P}$$.

Current Electricity

Five current carrying conductors meet at a point '$\mathrm{O}' as shown in figure. The magnitude and direction of the current in conductor 'O P$' is

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