Question 307: Dual Nature of Matter and Radiation

Question

When a light of wavelength $300 \mathrm{~nm}$ fall on a photoelectric emitter, photo electrons are emitted. For another emitter light of wavelength $600 \mathrm{~nm}$ is just sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

Accepted Answer

Work function $\phi_0=\frac{\mathrm{hc}}{\lambda_0}$
$\begin{aligned}
	herefore \quad \phi_0 & \propto \frac{1}{\lambda_0} \
& \frac{\phi_{01}}{\phi_{0_2}}=\frac{\lambda_{0_2}}{\lambda_{0_1}}=\frac{600}{300}=\frac{2}{1}
\end{aligned}$

Answer

1 : 2

Answer

2 : 1

Answer

4 : 1

Answer

1 : 4

Dual Nature of Matter and Radiation

When a light of wavelength 300 \mathrm{~nm} fall on a photoelectric emitter, photo electrons are emitted. For another emitter light of wavelength 600 \mathrm{~nm} is just sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

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