Question 349: Dual Nature of Matter and Radiation

Question

The light of wavelength $\lambda$ incident on the surface of metal having work function $\phi$ emits the electrons. The maximum velocity of electrons emitted is [ $c=$ velocity of light, $h=$ Planck's constant, $m=$ mass of electron]

Accepted Answer

photoelectric effect, the maximum kinetic energy possessed by the particle,
$\begin{aligned}
\mathrm{KE}_{\max } & =h v-\phi \
\frac{1}{2} m v^2 & =\frac{h c}{\lambda}-\phi \quad \left(\because v=\frac{c}{\lambda}ight)\
\Rightarrow \quad v^2 & =\frac{2(h c-\phi \lambda)}{\lambda m} \
v & =\left[\frac{2(h c-\lambda \phi)}{m \lambda}ight]^{1 / 2}
\end{aligned}$

Answer

$\left[\frac{2(h v-\phi) \lambda}{m c}\right]$

Answer

$\left[\frac{2(h c-\lambda \phi)}{m \lambda}\right]^{1 / 2}$

Answer

$\left[\frac{2(h c-\lambda)}{m \lambda}\right]^{1 / 2}$

Answer

$\left[\frac{2(h c-\phi)}{m \lambda}\right]$

Dual Nature of Matter and Radiation

The light of wavelength \lambda incident on the surface of metal having work function \phi emits the electrons. The maximum velocity of electrons emitted is [ c= velocity of light, h= Planck's constant, m= mass of electron]

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