Question 334: Dual Nature of Matter and Radiation

Question

The light of wavelength '$$\lambda$$' is incident on the surface of metal of work function $$\phi$$ and emits the electron. The maximum velocity of electron emitted is [$$\mathrm{m}=$$ mass of electron and $$\mathrm{h}=$$ Planck's constant, $$\mathrm{c}=$$ velocity of light]

Accepted Answer

We have $$\frac{1}{2} m v_{\max }^2=\frac{h c}{\lambda}-\phi=\frac{h c-\phi \lambda}{\lambda}$$
$$\begin{array}{ll}
	herefore \quad \mathrm{V}_{\max }^2=\frac{2(\mathrm{hc}-\phi \lambda)}{\mathrm{m} \lambda} \\
	herefore \quad\mathrm{V}_{\max }=\sqrt{\frac{2(\mathrm{hc}-\phi \lambda)}{\mathrm{m} \lambda}}
\end{array}$$

Answer

$$\left[\frac{2(h c-\lambda)}{\mathrm{m} \lambda}\right]^{\frac{1}{2}}$$

Answer

$$\left[\frac{2(h c-\phi) \lambda}{m c}\right]$$

Answer

$$\left[\frac{2(h c-\lambda)}{m \lambda}\right]$$

Answer

$$\left[\frac{2(\mathrm{hc}-\lambda \phi)}{\mathrm{m} \lambda}\right]^{\frac{1}{2}}$$

Dual Nature of Matter and Radiation

The light of wavelength '$\lambda' is incident on the surface of metal of work function \phi and emits the electron. The maximum velocity of electron emitted is [\mathrm{m}= mass of electron and \mathrm{h}= Planck's constant, \mathrm{c}=$ velocity of light]

Choose the correct answer: