Question 162: Dual Nature of Matter and Radiation

Question

Given figure shows few data points in a phot electric effect experiment for a certain metal. The
minimum energy for ejection of electron from its surface is:
(Plancks constant h = 6.62 × 10
–34
J.s)
![](https://imagex.cdn.examgoal.net/jgy2xukf6is7vp/c8e74113-edd7-40d8-b545-a8eedb3e4192/3bf73150-f8bb-11ea-8293-3b6cc591631c/file-jgy2xukf6is7vq-320w.png)

Accepted Answer

K
max
= hf - $\phi $
$ \Rightarrow $ eV
0
= hf - $\phi $
at B V
0
= 0,  f = 5.5
$ 	herefore $ $\phi $ = hf
= ${6.62 	imes {{10}^{ - 34}} 	imes 5.5 	imes {{10}^{14}}}$ J
= ${{6.62 	imes {{10}^{ - 34}} 	imes 5.5 	imes {{10}^{14}}} \over {1.6 	imes {{10}^{ - 19}}}}$ eV
= 2.27 eV

Answer

2.10 eV

Answer

2.27 eV

Answer

2.59 eV

Answer

1.93 eV

Dual Nature of Matter and Radiation

Given figure shows few data points in a phot electric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is: (Plancks constant h = 6.62 × 10 –34 J.s)

Choose the correct answer: